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I get confused with arrays when it is taking more than two dimensions and same way with pointers. Most of questions are always about this? I so make mistakes some time. So could you explain how it's translated into instructions? I don't want to disassemble and figure out the whole day. So somebody will you do it for me?
for eg Something like that.

a literal string, like "Hello", is actually of type char* (or const char*), pointing to some location you don't care about (and shouldn't try to modify).

if you write: char student[]="Hello" - that creates a local array filled with these chars, size depends on the string size.
you could also write const char* student = "Hello", if you don't need a local array to modify.

now, adding another array level to that makes it an array of these:
char students[] [].

actually, that's a lie. that won't compile, because the first [] means an array of indeterminate size, to be determined by the data. you can't have an array of items of unknown size.
what you could do is make an array of char* pointers, that works: as for i'm not sure about the priority of operations. i would just avoid such humanly ambigous constructs where meaning isn't immediately clear.

Well something like that. What i really want to know is how arrays and pointers are internally dereferenced. Thanks for reply zloba

how arrays and pointers are internally dereferenced

why? are you taking a compiler course? whose "questions"?

you dereference or index an array or pointer - you get a dereferenced object of the item type. how it's done internally is up to the compiler.. say, the offset gets computed into a register, and then used somehow to access the value.

Declaring [tt]int array[3];[/tt] gives you pointer to three consecutive integer values, called [tt]array[/tt]. You can use either [tt]*(array + 1)[/tt] or [tt]array[1][/tt] to access the middle element.

Declaring [tt]int array_2[5][3];[/tt] gives you a pointer to five consecutive pointers to three consecutive integer values each. You can use [tt]array_2[ 0][/tt] to get the first of these pointers, which has the same type as [tt]array[/tt] above (a pointer to three consecutive integer values). [tt]array_2[ 0][1][/tt] will give you the middle element of that array.

If you are initializing this array like this:
...the values will be present in memory in just that order, consecutively.

n-dimensional arrays are just an extension of the principle. Always remember that you don't really get an n-dimensional array, but only pointers to pointers to pointers to one-dimensional arrays.

I hope this helps.