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Hi,
I have graduated . I have completed my BTech in Computer Science and Engineering . from College of Engineering , Trivadrum .


Bwi ha ha ha aha ha ha aha ha aha ah aha ah a aha ha ahah a aha aha ha ah.... What the heck!!!

Congrats!

Well done

, well done, I'm ages away from that, not even in uni yet... (want to study computer science)
But wouldn't it have been better to post this in general ramblings, or are you just being modest
Jules

suthers wrote: , well done, I'm ages away from that, not even in uni yet... (want to study computer science)
But wouldn't it have been better to post this in general ramblings, or are you just being modest
Jules

Well ,this has nothing to do with anything technical ,. so thought of putting it in the test forum . Anyways i do not know how to get into a uni in your country .But in India , All you need to do learn Physics , Chemistry and Math well . Your speed is really very very important , its like 120 questions in 120 minutes . No one will possibly answer all of the questions . Some questions are tricky .. very tricky (and no calculator by the way!)

eg Find the intergral of Intergral ( 1 / x^2) within the limits -5 to 3 . It is very easy to come up with something like

[ -2 / x ^ 3 ] within limits -3 to 3 = -2 / 9 - 2/125 = -250 -18 / 125 * 9 = -268 / 1125 , but the answer is wrong coz the integral is not defined when x = 0 .

Another one , find the number of rectangles in a chessboard ? [ hint : C ( 9 , 2 ) * C (9 ,2) ]

Regards
Sandeep Mathew

1 minute to solve the how many rectangles in a chessboard, seriously?
It took me a few minutes (I didn't get your clue at first, but am I right in thinking 1296?)
The first question in this years maths AQA GCSE was something like this.
type x/y into you calculator (x and y were simple integers...)
1) write all the numbers shown by your calculator.
2) write it to 4 decimal places.

Wow, those one nearly got me
Jules

edit: general ramblings does say it is for everything else, not necessarily about computing...

(1+2+3+4+5+6+7+8)^2 works too

Yes suthers , you are right . . The answer is 1296 = 36^2 . A rectangle is formed when 4 lines meet . There are 9 lines breadth wise and 9 lines length wise . 2 lines in breadth side can be chosen in C(9,2 ) ways, Similary 2 lines in length side can be chosen in C(9,2) . Therefore totally C( 9 , 2 ) * C ( 9 , 2 ) . = 1296 .

Wow combuster , you really think like a computer scientist . Let me try to guess your way of thinking .

Consider a 1 X 1 chess board , it trivially has only one rectangle .
Consider a 2 X 2 chess borad , it has 9 rectangles = ( 1 + 2 ) ^ 2.
...
Consider a n x n chess borad , it has (Sigma n) ^ 2 rectagle
= ( n * (n+1) / 2 ) ^ 2 rectangles . I think you derived the results using principles of Mathematical Induction (not exactly ,almost)

Regards
Evil Sandeep

That's a different way to explain it. I was thinking about it the other way around

1 option of size 8
2 options of size 7
...
8 options of size 1
compute sum, then take powers for each dimension.

Well done.. Time to dance!@