Re:Another Puzzle
Posted: Sun Aug 01, 2004 4:07 am
Alright no one asked, but I can explain this one.
Dealing with the first and last numbers, we have three options,
1XXX3 2XXX6 3XXX9
We know this because X[sub]1[/sub] cannot be bigger than 3 or X[sub]5[/sub] will be a two digit number, same in that X[sub]2[/sub] cannot be larger than 5 or X[sub]4[/sub] will be too large.
Now to the other three digits, again there are only three options,
X529X X418X X307X
Because X[sub]2[/sub] cannot be less than 3 or X[sub]3[/sub] will be negative.
The reason that we only looked at those two numbers is that all other numbers can be derived from them, according to given statement.
X[sub]5[/sub] = 3X[sub]1[/sub]
X[sub]3[/sub] = X[sub]2[/sub] - 3
X[sub]4[/sub] = X[sub]2[/sub] + 4
So now we just look for the combination that answers the question, Which has three pairs which add up to 11, our choices
15293 =1 pair 25296=3 pair 35299=2 pair
14183 =1 pair 24186=0 pair 34189=1 pair
13073 =0 pair 23076=0 pair 33079=0 pair
25296
Dealing with the first and last numbers, we have three options,
1XXX3 2XXX6 3XXX9
We know this because X[sub]1[/sub] cannot be bigger than 3 or X[sub]5[/sub] will be a two digit number, same in that X[sub]2[/sub] cannot be larger than 5 or X[sub]4[/sub] will be too large.
Now to the other three digits, again there are only three options,
X529X X418X X307X
Because X[sub]2[/sub] cannot be less than 3 or X[sub]3[/sub] will be negative.
The reason that we only looked at those two numbers is that all other numbers can be derived from them, according to given statement.
X[sub]5[/sub] = 3X[sub]1[/sub]
X[sub]3[/sub] = X[sub]2[/sub] - 3
X[sub]4[/sub] = X[sub]2[/sub] + 4
So now we just look for the combination that answers the question, Which has three pairs which add up to 11, our choices
15293 =1 pair 25296=3 pair 35299=2 pair
14183 =1 pair 24186=0 pair 34189=1 pair
13073 =0 pair 23076=0 pair 33079=0 pair
25296