Kind of. Alef-null is (I believe.) the infinite set of natural numbers. C is the infinite set of real numbers, called "continuity" because of its continuous property. It's an open problem of set theory whether there's any level of infinite set between the absolutely discrete alef-null and the absolutely continuous C.
Someone who's had more than a passing introduction to set theory could explain it better.
Also, if Alef is already a language, when will someone update it to make Bet?
Syscall types
Wikipedia, article Aleph=One:Crazed123 wrote:Kind of. Alef-null is (I believe.) the infinite set of natural numbers. C is the infinite set of real numbers, called "continuity" because of its continuous property. It's an open problem of set theory whether there's any level of infinite set between the absolutely discrete alef-null and the absolutely continuous C.
Someone who's had more than a passing introduction to set theory could explain it better.
Also, if Alef is already a language, when will someone update it to make Bet?
Wikipedia, article Set:Wikipedia wrote:Aleph-null (\aleph_0) is by definition the cardinality of the set of all natural numbers
Wikipedia wrote:\mathbb{C}, denoting the set of all complex numbers.
Candy: The set 'C' representing all complex numbers is denoted by a script capital C. As are Z,R,W etc for integer, real, rationals. This would differentiate it from another set, 'C'. (I'm sure that letter must have been used multiple times in set theory).
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As crazed said, it is an open problem whether the cardinality of the set of all real numbers > that of the set of all natural numbers. Is one infinity bigger than another?
JamesM
The cardinality of the set of all natural numbers - must mean that aleph-null is some form of infinity then... :SAleph-null (\aleph_0) is by definition the cardinality of the set of all natural numbers
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I really should STFW before I post...the aleph numbers are a sequence of numbers used to represent the cardinality (or size) of infinite sets.
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As crazed said, it is an open problem whether the cardinality of the set of all real numbers > that of the set of all natural numbers. Is one infinity bigger than another?
JamesM
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I think this "C" means the cardinality of the set of real numbers, rather than the set of complex numbers. (the cardinality of C (superset of C) is C squared, equals C ).
And btw, C > Aleph-0. So much for an open problem.
And btw, C > Aleph-0. So much for an open problem.
We know that C > Alef-null. The open problem is if they are the 1 and 0, respectively, of set cardinalities or whether any X exists for C > X > Alef-null.Combuster wrote:I think this "C" means the cardinality of the set of real numbers, rather than the set of complex numbers. (the cardinality of C (superset of C) is C squared, equals C ).
And btw, C > Aleph-0. So much for an open problem.
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From what I've heard either of C = Aleph-1 and C != Aleph-1 can be used with current mathematics without losing consistency. To me, that sounds like its impossible to prove that only one is correct.Crazed123 wrote:We know that C > Alef-null. The open problem is if they are the 1 and 0, respectively, of set cardinalities or whether any X exists for C > X > Alef-null.
There must be some things in life we will never understand