typeid operator

[Neo]

The output of the following program

Code: Select all

#include<iostream.h>
class yourclass { };
int main()
{
        int i;         
        float j;
        char c;
        double db;
        yourclass a;
        cout << " i is " << typeid(i).name() << endl;
        cout << " j is " << typeid(j).name() << endl;
        cout << " db is " << typeid(db).name() << endl;
        cout << " c is " << typeid(c).name() << endl;
        cout << " a is " << typeid(a).name() << endl;
        return 0;
}

is

i is i
j is f
db is d
c is c
a is 9yourclass

Now how come the name of the user defined type (myclass) is printed (in full) whereas the standard datatypes are just one char?
What is the reason behind this?

[Solar]

It's "implementation defined", i.e. you should ask the compiler builders that question. I'd guess efficiency (both in storage space and comparison times).

BTW, VisualStudio 6 delivers:

i is int
j is float
db is double
c is char
a is class yourclass

Oh, and iostream.h is deprecated. Use <iostream>...