Poker probs/stats

Zacariaz · Post by **Zacariaz** » Sat Apr 05, 2008 9:28 pm

Yes, I've taken the poker stuff up again, but here in the planing phase I have one (and probably more to come) question.
It's really very simple, all I gotta do is figuring out how many possible combinations of the different types of hand are possible. I think I have the correct results, but I do need them verified and I hope one of you can help with that.

I looks like this:

straight flush: 10*4 = 40
4 of a kind: 13*(12*4) = 624
full house: ((4*3*2)/3!*13)*((4*3)/2!*12) = 3744
flush: (52*12*11*10*9)/5! = 5148
straight: (4^5-4)*10 = 10200
3 of a kind: ((4*3*2)/3!*13)*(12*4)*(11*4) = 109824
2 pairs: ((4*3)/2!*13)*((4*3)/2!*12)*(11*4) = 247104
1 pair: ((4*3)/2!*13)*(12*4)*(11*4)*(10*4) = 6589440
high card: (52*51*50*49*48)-(6589440+247104+109824+10200+5148+3744+624+40) = 304909076

I have tried to write the calculations in an explainatory way, but really as long as I get the results confirmed (or deconfirmed) I'm happy.

Thank you.

Hangin10 · Post by **Hangin10** » Sat Apr 05, 2008 10:34 pm

According to wikipedia, your flush calculation is off, along with the last 4 items on your list: http://en.wikipedia.org/wiki/Poker_hands

Zacariaz · Post by **Zacariaz** » Sat Apr 05, 2008 11:19 pm

I forgot to subtract 40 from the flush.
1 and 2 pairs plus 3 of a kind is simular mistakes.
Anyway, thanks for pointing me to the wiki article.