A call does not work

[ateno3]

Hello everybody.
I have a little problem with my OS. In the initial loading of my OS, GRUB loads a initrd (Initial RAM Disk) which contains a plain binary that I copy to another address in the memory which is controled by the OS and it's preparated to run applications. After I copy the binary, I try to call it, because I know where the entry point is. Besides, to know if the call has properly worked, the code writes in an address that I also know some numbers that I can read from the debugger.
The code is something like that:
My OS:

Code: Select all

void (*call)(void* param) = ((void(*)(void* param)) address; // The address is in the MB 16 and, yes, it's mapped.
call(data); // where data is a struct which contains some information that application needs. Besides, there are also a CRC so
               // I can check whether the code have done its work fine. The problem is that the code seems not to work (in fact, it seems
               // that it is not called at all ) because the structure isn't modified (when the struct. must have been changed). Moreover, 
               // when I look at the address I said before, there are nothing.

Binary

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unsigned int* address2check = (unsigned int*)0x1400000; // Again, it's mapped and there are no mmio mapped to that address.
*addres2chechk = 0x1234567; // A random number I put.
// Then I use the struct info and I modify its contents.

PS. My English is not my mother tongue and, as you all can see, my level isn't too high so, sorry
PS2. If everyone needed more information, or code, do not doubt to ask me for it.

[sortie]

Don't use flat binaries. Use the ELF container format. Use paging and load the ELF executable at the location it was linked at.

[ateno3]

The problem about doing what you're saying, is I have not implemented it yet. Moreover, VirtualBox allows me to see the RAM to check if the code is properly, and it is.
But thank you a lot!!!