Few newbies questions

[Hery]

1. [asm] In Intel synatx (NASM) i've written:

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mov word [es:00h], ax

, what i have to write in AT&T??
2. [C] when i write code like this:

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int (*something) (arguments) =0x80d09;
 (*something) (arguments);

Does it call address cs:80d09h or 80d09h (physical)?
3. [linker]I've got 16bit ELF object file (gcc), and i need good linker which made 16 bit binary file. Result file have to can run in alone (it'll be OS).

Thanks.

[bubach]

mov word [es:00h]
?

thats not valid. you must have missed something.

[Hery]

oh, yes, sorry. now is ok.

[MisterIO]

You're giving to 'something' 0x80d09,so you're talking about 32bit protected mode.Even without trying that code,do you really think that with that instruction you could break the hardware protection?
If you are not talking about 32bit protected mode,do you really think that you can give 0x80d09 to a 16bit variable?Also your question is wrong because if you are in real mode cs:'(16 bit number)'h is a "physical" address,because there is not virtual memory in real mode!Maybe it could work with something like :
far int etc. etc.
but I don't know,it depends on your compiler!

[Hery]

i read that logical address mean:

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0x6000:0x5FA6

(segment:offset) and physical:

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0x6000*16+0x5FA6=0x65FA6

(segment*16+offset)
UPDATE: it isn't important i can write it easier, what about other questions??