what did i miss about ebp?
Posted: Sat Jan 26, 2008 10:33 am
hi
i have a routine with a variable number of parameters
the number of parameters passed to the routine is fetched from within the routine via:
i.e., its the last parameter pushed
this still works fine. but then im trying to process the "real" parameters in a loop by loading ebp+12 into ebx and then adding 4 to ebx in each cycle. here i noticed the following strange behaviour:
putunsint displays an unsigned integer as the name suggests...
the first putunsint statement shows me the correct value, i.,e. the value that i want to see
the second putunsint shows me something different! how can this be if ebp and ebx contain the same value (putunsint DOES preserve the ebx register!)
any clues?
thanks
martin
i have a routine with a variable number of parameters
the number of parameters passed to the routine is fetched from within the routine via:
Code: Select all
mov([ebp+8],eax);this still works fine. but then im trying to process the "real" parameters in a loop by loading ebp+12 into ebx and then adding 4 to ebx in each cycle. here i noticed the following strange behaviour:
Code: Select all
mov(ebp,ebx);
putunsint([ebp+12]);
putunsint([ebx+12]);the first putunsint statement shows me the correct value, i.,e. the value that i want to see
the second putunsint shows me something different! how can this be if ebp and ebx contain the same value (putunsint DOES preserve the ebx register!)
any clues?
thanks
martin
