More keyboard trouble

[vbbrett]

Hello all,
Help is needed in getting this code to work. I have tried for about a week at debugging. So, now it's your turn to play with it.
Whenever I type using this code (I've tried this on 3 different computers) it always comes out with 2 or 3 of the same letter. Striking the key VERY quickly produces 1 letter on the screen. Why is this happenning and how can I resolve this issue?

This is very messy. I now. Work with me please. Any pointers would be nice.

Brett

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[Curufir]

Code: Select all

if (intnumber = 0x51) { keyhandler(); }
if (intnumber = 0x50) { ticks++; }

Both of these evaluate to true, so you call the keyhandler() function every tick.

Side-Note: Your code style is very difficult to read. I'd seriously advise you to tidy it up before the source grows much further (Unless the formatting somehow got removed on posting).

[Pype.Clicker]

case 'a': kprintf("a", xpos, ypos); pdat=1; break;
case 'b': kprintf("b", xpos, ypos); pdat=1; break;
case 'c': kprintf("c", xpos, ypos); pdat=1; break;
case 'd': kprintf("d", xpos, ypos); pdat=1; break;

aargh! :O

Code: Select all

if (intnumber = 0x51) { keyhandler(); }
if (intnumber = 0x50) { ticks++; }

these should be 'intnumber == 0x51' ... typical mistake for someone who comes into C and for someone who wrote C code all the night :-p

I'm not sure a "if (...) call_sub_handler()" is the nicest way to deal with interrupts at all ...