Code: Select all
typedef struct pageframe
{
lklist_head_t listnode;
struct
{
uint8_t order: 4;
bool free: 1;
bool reserved: 1;
uint32_t ign: 26;
};
spinlock_t lock;
uintptr_t addr;
} pageframe_t;
In my opinion, I have to find a free space to store the initial page descriptors, it cannot overlap with the kernel address. And I think that there are some other structs reserved in the memory, such as ACPI table? It is easy for me to find where the kernel is, but not other structs.
In the other words, if I want to initialize the physical memory management, I have to find a free space to store my page descriptors, but the page descriptors tell me where is free or not. Currently, I don't know if is there another way to indicate which space is free. Saving it into bss section takes a lot of memory. In the worst situation (in my mind), this allocator takes a least 1/128 memory to store the page descriptors (for example, 128MB in 16GB).
Could anyone tell me whether there is another way to find a space to save the descriptors? or just point out problems in my logic? I am using stivale2 (limine) protocol to boot the kernel. I think the memory map might help me solve the problem. What if possible I just initialize all the memory regions marked as "available"?
Code: Select all
#define PAGE_MAX_SIZE (4 * 1024 * 1024)
#define PAGE_MAX_ORDER 10
typedef struct pageframe_list
{
lklist_head_t handle;
uint32_t count;
} pageframe_list_t;
typedef struct pageframe_block
{
uint32_t count;
uintptr_t addr;
pageframe_list_t freelist[PAGE_MAX_ORDER + 1];
} pageframe_node_t;