I've run into a really strange bug.
Recently I've been working on fixing my task scheduler and stuff. I decided to try to fix my fault handler since it crashed the entire OS when one program crashes.
When I use a test program that reads from address 0 (which is unmapped), it catches it and kills the process as it should. The OS continues to run fine. I can run programs, exit them, etc.
However, when I run the test program a second time, it causes a triple fault.
My first attempt to figure out what was happening was to add "-d int" to QEMU. However, QEMU spat out a hundred or so of the following:
Then after those it printed:check_exception old: 0xffffffff new 0xe
174874: v=0e e=0000 i=0 cpl=0 IP=0008:c0101526 pc=c0101526 SP=0010:c0155a41 CR2=00000000
My second attempt was to step through and compare registers in both instances.check_exception old: 0xffffffff new 0xd
175039: v=0d e=001a i=0 cpl=0 IP=0008:000f06ac pc=000f06ac SP=0010:00000fc8 env->regs[R_EAX]=000f6206
check_exception old: 0xd new 0xd
175040: v=08 e=0000 i=0 cpl=0 IP=0008:000f06ac pc=000f06ac SP=0010:00000fc8 env->regs[R_EAX]=000f6206
check_exception old: 0x8 new 0xd
(Triple Fault)
Unfortunately, the instruction that caused the triple fault was in usermode, so this was difficult.
From what I could tell, important registers like esp, eip, cr3, etc were exactly the same.
What other methods can I use to figure this out?
(Code will be posted in next post)