'80387 instructions aren't allowed' when compiling ISR

[pyd1]

I tried to create an ISR using the GCC attribute, but it doesn't work. This is the code:

Code: Select all

#include <stdint.h>

struct interrupt_frame {
    uint16_t ip;
    uint16_t cs;
    uint16_t flags;
    uint16_t sp;
    uint16_t ss;
} __attribute__((packed));

__attribute__((interrupt)) void irq0(struct interrupt_frame* frame)
{
}

But when I compile it, GCC throws an error:

Code: Select all

$ i686-elf-gcc -ffreestanding -c handler.c -o handler.o
handler.c: In function 'irq0':
handler.c:12:1: sorry, unimplemented: 80387 instructions aren't allowed in an interrupt service routine
   12 | {
      | ^

When I tried to search online, I couldn't find any examples using the GCC attribute, and I could not find any mentions of this error. What am I doing wrong? Is it even possible?
Thanks!

[Octocontrabass]

Since GCC doesn’t preserve SSE, MMX nor x87 states, the GCC option -mgeneral-regs-only should be used to compile interrupt and exception handlers.

From the GCC manual.

I don't think that interrupt_frame struct is correct. Why are all of its members uint16_t instead of uint32_t?