IRQ error on qemu

[aemgoborges]

Hello guys , my IRQ's are not working when i remap the pic and register the Interrupt routines and call irq_install in main function i got this message from qemu : Booting From ROM , and my os not boot

code of error:

Code: Select all

void remap_pic()
{
outportb (0x20, 0x11);
outportb (0xA0, 0x11);
outportb (0x21, 0x20);
outportb (0xA1, 0x28);
outportb (0x21, 0x04);
outportb (0xA1, 0x02);
outportb (0x21, 0x01);
outportb (0xA1, 0x01);
outportb (0x21, 0x0);
outportb (0xA1, 0x0);
}



void irq_install()
{

  remap_pic();

  idt_set_gate (32, (unsigned)irq0, 0x08, 0x8E);
  idt_set_gate (33, (unsigned)irq1, 0x08, 0x8E);
  idt_set_gate (34, (unsigned)irq2, 0x08, 0x8E);
  idt_set_gate (35, (unsigned)irq3, 0x08, 0x8E);
  idt_set_gate (36, (unsigned)irq4, 0x08, 0x8E);
  idt_set_gate (37, (unsigned)irq5, 0x08, 0x8E);
  idt_set_gate (38, (unsigned)irq6, 0x08, 0x8E);
  idt_set_gate (39, (unsigned)irq7, 0x08, 0x8E);
  idt_set_gate (40, (unsigned)irq8, 0x08, 0x8E);
  idt_set_gate (41, (unsigned)irq9, 0x08, 0x8E);
  idt_set_gate (42, (unsigned)irq10, 0x08, 0x8E);
  idt_set_gate (43, (unsigned)irq11, 0x08, 0x8E);
  idt_set_gate (44, (unsigned)irq12, 0x08, 0x8E);
  idt_set_gate (45, (unsigned)irq13, 0x08, 0x8E);
  idt_set_gate (46, (unsigned)irq14, 0x08, 0x8E);
  idt_set_gate (47, (unsigned)irq15, 0x08, 0x8E);



}

when i not call irq_install , on main my os work , what's is happening?

[BrightLight]

Does it triple fault? Is a different IRQ handler called? Do you have software interrupts working before hardware IRQs? You need to give more information than a code snippet.

[aemgoborges]

yes i have software interrupts working , not triple fault

[BrightLight]

Then define "IRQ error". What does IRQ error mean? What happens on IRQ?

[aemgoborges]

irq error that i said is because when every time a call irq set up routine in my kernel main qemu not boot my system its says boot from rom

[BrightLight]

QEMU says "Booting from ROM..." whenever you boot your kernel using the -kernel command-line option. What IRQ are you waiting to receive? Without calling your IRQ initialization code, what happens? What does QEMU show?

[aemgoborges]

without irq initialization code my os on qemu works fine . i`m not waiting an interrupt . i'm just put irqs on idt and call the code of initialization on kernel main

[Combuster]

Do you happen to have a CLI; HLT; pair somewhere in your code? In QEMU this is an infamous way to prevent any updates to the screen from showing.