real mode memory addressing

[tom9876543]

ok i know this may be a dumb question but i just want to make sure

8000:1234 = 81234h? just like 8123:0004 would equal the same?

for all i understand say the bootloader is 0000:7c00
could i do this

1000: 0000-ffff = 64 kb 10000h to 1ffffh
then 2000: 0000- ffff another 64 kb 20000h- 2ffffh
am i able to acsess this with no problems, i know at for example i have to watch out for example 0xb800 but do i have to watch out for that in every segment? do i have to watch out for

0000:b800
1000:b800
2000:b800

im sorry if this is all confusing to ask, but im trying to kill two birds with one stone

Question 1:
Yes 8000:1234 is the same as 8123:004 .

Question 2:
Do a search in Google for the reserved regions of memory in the first 1 megabyte. The answer should be on this web site somewhere.

Question 3:
You have misunderstood b800. That is the SEGMENT, not the offset. b800:XXXX are the addresses you should avoid.

[VolTeK]

i got that..

Love4Boobies: could u be anymore mouthy?


1. ok?

2. checked google, why do u think i am barely here anymore, i get my information, barely, if at all, from here anymore.

3. i was told that earlier

[Love4Boobies]

Love4Boobies: could u be anymore mouthy?

You asked, you've been answered, you asked again, I tried explaining another way. Where did I go wrong?

[AJ]

Locked - this thread is going nowhere and some background reading (along with reading replies to the thread) is required.