QEMU throws an error after interrupts are enabled

[ruisleipa]

QEMU throws the following error when running my kernel:

Code: Select all

qemu: fatal: Trying to execute code outside RAM or ROM at 0xc90000c9

EAX=00000000 EBX=00026260 ECX=00000000 EDX=000003d5
ESI=000263d3 EDI=000263ec EBP=00067edc ESP=001051f4
EIP=c90000c9 EFL=00000002 [-------] CPL=0 II=0 A20=1 SMM=0 HLT=0
ES =0010 00000000 ffffffff 00cf9300
CS =0008 00000000 ffffffff 00cf9a00
SS =0010 00000000 ffffffff 00cf9300
DS =0010 00000000 ffffffff 00cf9300
FS =0010 00000000 ffffffff 00cf9300
GS =0010 00000000 ffffffff 00cf9300
LDT=0000 00000000 0000ffff 00008000
TR =0000 00000000 0000ffff 00008000
GDT=     0010600a 00000017
IDT=     00106060 000007ff
CR0=60000011 CR2=00000000 CR3=00000000 CR4=00000000
CCS=00000000 CCD=001051f4 CCO=EFLAGS  
FCW=037f FSW=0000 [ST=0] FTW=00 MXCSR=00001f80
FPR0=0000000000000000 0000 FPR1=0000000000000000 0000
FPR2=0000000000000000 0000 FPR3=0000000000000000 0000
FPR4=0000000000000000 0000 FPR5=0000000000000000 0000
FPR6=0000000000000000 0000 FPR7=0000000000000000 0000
XMM00=00000000000000000000000000000000 XMM01=00000000000000000000000000000000
XMM02=00000000000000000000000000000000 XMM03=00000000000000000000000000000000
XMM04=00000000000000000000000000000000 XMM05=00000000000000000000000000000000
XMM06=00000000000000000000000000000000 XMM07=00000000000000000000000000000000
Aborted

I have narrowed the problem, and it happens after interrupts are enabled in main() in main.c.
I have also tried to add hlt:s to the code to the interrupt and exception handlers but the error still comes up.

I would really appreciate even pointing to the place where the error might occur.

Thanks in advance.

BTW the sources are in the tarball

[Combuster]

Hint (in idt.c):

Code: Select all

	base_hi=(base<<8);
	base_lo=(base&0x00ff);

[ruisleipa]

Thank you really much! I am happy when I know that there still are people who are willing to help newbies

[suthers]

Thank you really much! I am happy when I know that there still are people who are willing to help newbies

Don't worry there are loads of people who are ready to help beginners if you follow the proper procedure and have the required knowledge
Jules