what did i miss about ebp?

[sancho1980]

hi

i have a routine with a variable number of parameters
the number of parameters passed to the routine is fetched from within the routine via:

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mov([ebp+8],eax);

i.e., its the last parameter pushed

this still works fine. but then im trying to process the "real" parameters in a loop by loading ebp+12 into ebx and then adding 4 to ebx in each cycle. here i noticed the following strange behaviour:

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mov(ebp,ebx);
putunsint([ebp+12]);
putunsint([ebx+12]);

putunsint displays an unsigned integer as the name suggests...

the first putunsint statement shows me the correct value, i.,e. the value that i want to see
the second putunsint shows me something different! how can this be if ebp and ebx contain the same value (putunsint DOES preserve the ebx register!)

any clues?

thanks

martin

[sancho1980]

sorry for the stupid question

i had completely forgotten that i had loaded ss with a completely different segment than ds